C++ 求一维数组中各元素的最大值、最小值和平均值

2023-07-26 14:18发布

#includeusing namespace std;void process(float a[],int n) { float min,

#includeusing namespace std;void process(float a[],int n) { float min,
3条回答
2023-07-26 14:41

#include <iostream>

using namespace std;

void process(float arr[], int len)
{
float temp;
for(int i = 0; i < len - 1; ++i)
{
for(int j = 0; j < len - i - 1; ++j)
{
if(arr[j] > arr[j+1])
{
temp = arr[j];
arr[j] = arr[j+1];
arr[j+1] = temp;
}
}
}
cout << "最小元素为 : " << arr[0] << endl;
cout << "最大元素为 : " << arr[len-1] << endl;
}

void print(float arr[], int len)
{
int i = 0;
while(i != len)
{
cout << arr[i] << " ";
if( (i+1) % 6 == 0) cout << endl;
++i;
}
}

int main()
{
float a[24]={2,1,4,45,23,33,-7,8,5,9,0,-4,66,12,55,33,32,11,63,14,88,-9,23,6};
process(a, 24);
print(a, 24);
return 0;
}

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