2022-04-13 12:53发布
解：令f(x)= 2x4 +7x3 -2x2 -13x+6=0
f(x)=(x-x1 )(x-x2 )(x-x3 )„„(x-xn )
8、求根法
121注：y² =(x+ x ) = x² + x² +2
=(x+1)2(2x-1)(x-2)
11=x² (x+ x +2)(2x+ x -5)
例8、分解因式2x 4 +7x3 -2x2 -13x+6
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解：令f(x)= 2x4 +7x3 -2x2 -13x+6=0
f(x)=(x-x1 )(x-x2 )(x-x3 )„„(x-xn )
8、求根法
121注：y² =(x+ x ) = x² + x² +2
=(x+1)2(2x-1)(x-2)
11=x² (x+ x +2)(2x+ x -5)
例8、分解因式2x 4 +7x3 -2x2 -13x+6
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